Java 解析文件后缀名(扩展名)的几种方法
时间:2022-08-10
1、使用FilenameUtils.getExtension来获取扩展名
maven配置:
<dependency> <groupId>commons-io</groupId> <artifactId>commons-io</artifactId> <version>2.4</version> </dependency>
String ext1 = FilenameUtils.getExtension("/path/to/file/foo.txt"); //returns "txt" String ext2 = FilenameUtils.getExtension("bar.exe"); //returns "exe"
2、通过使用lastIndexOf和substring方法来得到扩展名
String extension = "";
int i = fileName.lastIndexOf('.');
if (i > 0) {
extension = fileName.substring(i+1);
}
或
String extension = "";
int i = fileName.lastIndexOf('.');
int p = Math.max(fileName.lastIndexOf('/'), fileName.lastIndexOf('\\'));
if (i > p) {
extension = fileName.substring(i+1);
}
3、使用Guava库的Files工具类获取扩展名
maven配置:
<dependency>
<groupId>com.google.guava</groupId>
<artifactId>guava</artifactId>
<version>17.0</version>
</dependency>
String path = "c:/path/to/file/foo.txt";
String ext = Files.getFileExtension(path);
System.out.println(ext); //prints txt
4、Android上可以使用的方法
String ext = android.webkit.MimeTypeMap.getFileExtensionFromUrl(file.getName());
5、经过测试的getExtension获取扩展名方法
public static String getExtension(String fileName) { char ch; int len; if(fileName==null || (len = fileName.length())==0 || (ch = fileName.charAt(len-1))=='/' || ch=='\\' || //in the case of a directory ch=='.' ) //in the case of . or .. return ""; int dotInd = fileName.lastIndexOf('.'), sepInd = Math.max(fileName.lastIndexOf('/'), fileName.lastIndexOf('\\')); if( dotInd<=sepInd ) return ""; else return fileName.substring(dotInd+1).toLowerCase(); }
测试用例
@Test
public void testGetExtension() {
assertEquals("", getExtension("C"));
assertEquals("ext", getExtension("C.ext"));
assertEquals("ext", getExtension("A/B/C.ext"));
assertEquals("", getExtension("A/B/C.ext/"));
assertEquals("", getExtension("A/B/C.ext/.."));
assertEquals("bin", getExtension("A/B/C.bin"));
assertEquals("hidden", getExtension(".hidden"));
assertEquals("dsstore", getExtension("/user/home/.dsstore"));
assertEquals("", getExtension(".strange."));
assertEquals("3", getExtension("1.2.3"));
assertEquals("exe", getExtension("C:\\Program Files (x86)\\java\\bin\\javaw.exe"));
}
6、使用split方法来获取后缀名
String[] split = fullFileName.split("\\.");
String ext = split[split.length - 1];
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